This week’s question comes from a graduate student studying virology, who writes:

My professor recently said that really, the MOI doesn’t matter in a culture, it is the concentration of viral particles in the media that matters. Ie: if you have 10 million cells or one cell, but you are infecting the plate with 5mL of 100 million viral particles/mL, then the amount of virus interacting with each cell is not different in either scenario (pretending that it isn’t nearly impossible for that single cell to survive in culture alone). I argued with him, saying that the cytotoxicity to the single cell would certainly be increased. He then said that a student hadn’t argued with him about that in his 15 years of teaching and I promptly decided to get some evidence before I continued the discussion.

I’m not actually sure which side is correct. I know that concentration is certainly a large determinant for infectious events/cell. But, it is hard for me to understand why MOI wouldn’t be more important? The more I think about it the more I think that I may be wrong. But if you have two plates with equal numbers of cells, and you add 5 mL of media to one and 50mL of media to the other – assuming that the media is 100 million infectious particles/mL – would the higher MOI plate not result in more infectious events per cell?

My reply: What first jumps out at me is the fact that the professor is using the *no one ever argued with me about that* excuse to say that he/she is right. That is the exact role of a student, to ask questions, and it should never be discouraged. Students can ask the best questions because they are frequently unencumbered by the bias of a field.

Please tell your professor that both multiplicity of infection and concentration of viral particles matter, for different reasons. The multiplicity of infection (MOI) is the number of virus particles added per cell. If you add one million virus particles to one million cells in a culture plate, the MOI = 1. If you add ten million virus particles to one million cells, the MOI is 10.

However, if one million virus particles are added to one million cells, each cell will not be infected with one virus particle. How many cells are uninfected, or receive 1, 2, or more virus particles is determined by the Poisson distribution. At an MOI of 1, 37% of the cells are uninfected, 37% receive 1 particle, 18% receive 2 particles, and so on.

In theory, the number of particles that infect each cell is controlled by the MOI, not the virus concentration. However, when the concentration of virus particles is very low, attachment to cells will take a very long time. This is because virus attachment is governed by the concentrations of free virions and host cells. The rate of attachment can be described by the equation

dA/dt = k[V][H]

where [V] and [H] are the concentrations of virions and host cells, respectively, and k is a rate constant.

For a 6 cm culture dish with an area of 113 square cm, we typically infect with virus in a volume no greater than 0.1 – 0.2 ml. In this way virus attachment to cells will be essentially complete within 1 hr at 37 degrees C. If the same amount of virus were added in 10 ml of medium, the attachment would take much longer; however because the MOI is the same in both cultures, at the end of the adsorption period the number of infected and uninfected cells in both cultures would be the same.

To answer the reader’s last question:

But if you have two plates with equal numbers of cells, and you add 5mL of media to one and 50mL of media to the other – assuming that the media is 100 mill infectious particles/mL – would the higher MOI plate not result in more infectious events per cell?

The answer is yes – assuming you wait long enough for the viruses in the more dilute culture to attach to cells.

Comments on this entry are closed.

I am confused by this statement:

“But if you have two plates with equal numbers of cells, and you add 5mL of media to one and 50mL of media to the other – assuming that the media is 100 mill infectious particles/mL – would the higher MOI plate not result in more infectious events per cell?”

isn’t the 50ml of media a higher MOI?

5ml @ 100million / ml = 500 million virions

50ml @ 100million / ml = 5,000 million virions

a larger number of virions per a fixed amount of cells would result in a higher MOI, no?

Another important issue in this case is to differentiate number of particles with number of INFECTIOUS particles. The MOI is (usually, at least) calculated accordingly to the number of infectious units of a determined virus (an infectivity assay of some sort). This doesn’t correlate at all with the number of viral particles. For HIV for example, the ratio of infectious particles to total particles can be 1:10000.

That’s important because when people calculate the concentration of virus they usually derive from a quantitatively method (an ELISA for example) that doesn’t assess infectivity, and rather the total amount of produced particles (or the equivalent in some viral protein concentration).

Wouldn’t receptor density of the targets cells and/or the phenomenon of superinfection exclusion make these calculations a little more complex?

4 parameters matter a great deal when it comes to viral infection of cells: ratio of virus particles to cells, the density of the virus particles and cells, the time they are exposed to each other, and the temperature during their interaction. This is because both Brownian motion is the critical determinant of whether or not virus and cell will come into contact each each other. For all reasonable lengths of time (hours to days), it is the density of infectious virus particles that matters, not the MOI. This paper demonstrates this for bacteriophage but the physics apply to any virus. http://www.ncbi.nlm.nih.gov/pmc/articles/PMC137030/#r12

J Virol. 2002 Jun;76(11):5557-64.

Overcoming the phage replication threshold: a mathematical model with implications for phage therapy.

Kasman LM1, Kasman A, Westwater C, Dolan J, Schmidt MG, Norris JS.

It is not just determined by Poisson distribution. Because viruses are so small, it is also determined by Brownian motion.

The principles were worked out in the early 20th century by M. Schlesinger based on the work of Albert Einstein on Brownian motion. The reason I got started on this paper was that we were plating large phage libraries for phage display. We needed so many plates that we had to do it in two rooms. The titers varied considerably between the two rooms despite the same starting virus stock and all else being equal. We realized eventually that it was due to one room being several degrees warmer than the other. That led to reading on Brownian motion, and the rest is in this paper.

Laura Kasman (P.S. I’m a virologist. The A. Kasman on the paper is a mathematical physicist.)

I have a problem: how do you calculate virus particles per unit protein/ml. Using A354 can you do it? Can you use A280 to measure the protein?